Calculating Bond Order Method- 1 (to find bond order quickly, 1/2 bond order) Antibonding Electrons- According to the molecular orbital theory, Bond order is.

Configuration: σ 1 s 2 σ ∗ 1 s 2 σ 2 s 2 σ ∗ 2 s 2 σ 2 p z 2 π 2 p x 2 π 2 p y 2 π ∗ 2 p x 1 π ∗ 2 p y 1. From this configuration we can see that: The number of bonding electrons = 10 and the number of antibonding electrons = 6. So, we can finally conclude that the number of antibonding electrons in O 2 are = 6.

Configuration: σ 1 s 2 σ ∗ 1 s 2 σ 2 s 2 σ ∗ 2 s 2 σ 2 p z 2 π 2 p x 2 π 2 p y 2 π ∗ 2 p x 1 π ∗ 2 p y 1. From this configuration we can see that: The number of bonding electrons = 10 and the number of antibonding electrons = 6. So, we can finally conclude that the number of antibonding electrons in O 2 are = 6.: How to find bonding and antibonding electrons

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How to find bonding and antibonding electrons - Configuration: σ 1 s 2 σ ∗ 1 s 2 σ 2 s 2 σ ∗ 2 s 2 σ 2 p z 2 π 2 p x 2 π 2 p y 2 π ∗ 2 p x 1 π ∗ 2 p y 1. From this configuration we can see that: The number of bonding electrons = 10 and the number of antibonding electrons = 6. So, we can finally conclude that the number of antibonding electrons in O 2 are = 6.

How to find bonding and antibonding electrons - Configuration: σ 1 s 2 σ ∗ 1 s 2 σ 2 s 2 σ ∗ 2 s 2 σ 2 p z 2 π 2 p x 2 π 2 p y 2 π ∗ 2 p x 1 π ∗ 2 p y 1. From this configuration we can see that: The number of bonding electrons = 10 and the number of antibonding electrons = 6. So, we can finally conclude that the number of antibonding electrons in O 2 are = 6.

How to find bonding and antibonding electrons - Configuration: σ 1 s 2 σ ∗ 1 s 2 σ 2 s 2 σ ∗ 2 s 2 σ 2 p z 2 π 2 p x 2 π 2 p y 2 π ∗ 2 p x 1 π ∗ 2 p y 1. From this configuration we can see that: The number of bonding electrons = 10 and the number of antibonding electrons = 6. So, we can finally conclude that the number of antibonding electrons in O 2 are = 6. Bond Order Definition. Most of the time, bond order is equal to the number of bonds between two atoms. Exceptions occur when the molecule contains antibonding orbitals. Bond order is calculated by the equation: Bond order = (number of bonding electrons – number of antibonding electrons)/2 If bond order = 0, the two atoms are not bonded. Mar 16, · Bonding orbitals are overlapping molecular orbitals between two nuclei. An anti bonding orbital is located outside the region of two distinct nuclei. The electrons present in each anti bonding orbital are repulsive and .

Configuration: σ 1 s 2 σ ∗ 1 s 2 σ 2 s 2 σ ∗ 2 s 2 σ 2 p z 2 π 2 p x 2 π 2 p y 2 π ∗ 2 p x 1 π ∗ 2 p y 1. From this configuration we can see that: The number of bonding electrons = 10 and the number of antibonding electrons = 6. So, we can finally conclude that the number of antibonding electrons in O 2 are = 6.

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